Exercise 2 solution

    from datetime import datetime

    start = datetime(2026, 11, 2, 9, 15)
    end = datetime(2026, 11, 2, 17, 50)

    worked = end - start
    print(worked)                          # 8:35:00
    print(worked.total_seconds() / 3600)   # 8.583333333333334

    hours, rest = divmod(int(worked.total_seconds()), 3600)
    print(hours, rest // 60)               # 8 35

(All lines were run and printed exactly the values shown.)

Explanation: subtracting two datetimes gives a timedelta. Printing it shows
hours:minutes:seconds. total_seconds() turns it into one number you can do
arithmetic on. Do not use the .seconds attribute for this: it holds only the
seconds part left over after whole days are removed, so it is wrong for any
span of a day or more. divmod splits the total into whole hours and a
remainder in seconds.