Exercise 3: Vowel vs. Consonant Counter — Possible Solution
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sentence = input("Enter a sentence: ")

vowels = 0
consonants = 0

for ch in sentence:
    if ch.isalpha():
        if ch.lower() in "aeiou":
            vowels += 1
        else:
            consonants += 1

print(f"Vowels: {vowels}")
print(f"Consonants: {consonants}")

Example run:
Enter a sentence: The Quick Brown Fox
Vowels: 5
Consonants: 11

WHY THIS WORKS AS AN ANSWER
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The outer if ch.isalpha() check does the same job it did in this
lesson's own accumulator example — it silently skips spaces and any
punctuation before either counter ever gets touched. Once a
character has passed that filter, it's guaranteed to be a letter, so
the only remaining question is which of the two buckets it belongs
in. ch.lower() in "aeiou" handles both cases in one line: lowering
the character first means "A" and "a" are both correctly recognised
as vowels without needing to check for both cases separately in the
"aeiou" string itself.