Exercise 1: A List, Three Ways — Possible Solution
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shopping = ["milk", "eggs", "bread", "tea"]

print(", ".join(shopping))
print(" | ".join(shopping))
print("\n".join(shopping))

# join puts the separator BETWEEN items only, so there is nothing
# after "tea" in any of the three lines.

Output:
milk, eggs, bread, tea
milk | eggs | bread | tea
milk
eggs
bread
tea

WHY THIS WORKS AS AN ANSWER
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The separator is the string join is called on, so each version
differs only in that string. For the third, the separator is a
newline character, which means the whole list becomes ONE string
containing line breaks and a single print() writes all four lines.
join never adds a separator after the last item, which is the
difference from a loop that prints each item with end=', ': that
loop leaves a stray comma at the end.