Exercise 1: Calculating 10.0.5.0/27 — Possible Solution
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Given: 10.0.5.0/27

Step 1 -- host bits:
Per the chapter's own formula, host bits = 32 - n. With n = 27:
32 - 27 = 5 host bits.

Step 2 -- total addresses:
Per the chapter, total addresses = 2^(host bits) = 2^5 = 32.

Step 3 -- usable hosts:
Per the chapter, usable hosts = total addresses - 2 (subtracting the
network address and broadcast address) = 32 - 2 = 30.

Step 4 -- network address:
The network address is the given address with all host bits set to 0,
which for a /27 boundary within the last octet means finding the
nearest multiple of 32 (since the block size here is 32 addresses)
at or below .0 -- since 10.0.5.0 already sits exactly on a /27
boundary (0 is a multiple of 32), the network address is simply
10.0.5.0 itself.

Step 5 -- broadcast address:
The broadcast address is the network address plus (total addresses -
1), i.e. the last address in the 32-address block: 10.0.5.0 + 31 =
10.0.5.31.

Step 6 -- usable host range:
The usable range is everything between the network and broadcast
addresses, exclusive of both: 10.0.5.1 through 10.0.5.30.

Answers:
- Total addresses: 32
- Usable host range: 10.0.5.1 - 10.0.5.30
- Network address: 10.0.5.0
- Broadcast address: 10.0.5.31

WHY THIS WORKS AS AN ANSWER
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This applies the chapter's own formulas (host bits = 32-n, total =
2^(host bits), usable = total-2) step by step and derives the network/
broadcast addresses from the block size (32) rather than guessing,
arriving at a fully verified, self-consistent set of values.