Challenge 3: Hash Iteration and Filtering — Solution

scores = { philip: 82, alex: 55, jordan: 91, sam: 47 }

scores.each do |student, score|
  status = score >= 60 ? "pass" : "fail"
  puts "#{student}: #{status}"
end

passing = scores.select { |student, score| score >= 60 }
puts passing.inspect

=begin
Output:
philip: pass
alex: fail
jordan: pass
sam: fail
{philip: 82, jordan: 91}

Notes:
- scores.each do |student, score| destructures each key-value pair
  directly in the block parameters — student gets the symbol key, score
  gets the integer value, in that order.
- The ternary (score >= 60 ? "pass" : "fail") is used here instead of a
  full if/else since it's a short, single-expression choice — the kind of
  case a ternary suits well even though Ruby's if/else is itself an
  expression too.
- scores.select on a Hash keeps the Hash shape in its result (not an
  Array of pairs), which is why passing.inspect prints back out as
  {philip: 82, jordan: 91} rather than a list of [key, value] arrays.
=end