Challenge 3: Days Until a Parsed Deadline — Possible Solution
====================================================================

import datetime

deadline_str = "2026-12-25"
deadline = datetime.datetime.strptime(deadline_str, "%Y-%m-%d").date()

today = datetime.date.today()
days_remaining = (deadline - today).days

print(days_remaining)

Output (will vary depending on the actual current date):
169

WHY THIS WORKS AS AN ANSWER
------------------------------
datetime.datetime.strptime(deadline_str, "%Y-%m-%d") reuses the
chapter's own strptime() example directly — the format string
"%Y-%m-%d" tells Python exactly how to interpret "2026-12-25": %Y for
a 4-digit year, %m for a 2-digit month, %d for a 2-digit day, matching
the chapter's own %Y-%m-%d formatting example used with strftime.

strptime() always returns a full datetime (date AND time, defaulting
the time portion to midnight), so .date() is chained on the end to
extract just the date portion — this keeps it consistent with
datetime.date.today(), which is date-only, the same date-vs-datetime
distinction the chapter opened this section with.

datetime.date.today() reuses today's date exactly as introduced back
in Course 1, Chapter 9.

(deadline - today).days reuses the same date-subtraction-produces-a-
timedelta mechanic from Course 1's own Days Until a Date challenge
solution — subtracting one date from another gives a timedelta, and
.days extracts the whole number of days between them, which is
exactly what "days remaining" asks for.