Challenge 1: Safe Division Function — Possible Solution
====================================================================

def safe_divide(a, b):
    try:
        return a / b
    except ZeroDivisionError:
        return None

print(safe_divide(10, 2))
print(safe_divide(10, 0))

Output:
5.0
None

WHY THIS WORKS AS AN ANSWER
------------------------------
try: return a / b reuses the chapter's own 10 / 0 example almost
exactly, wrapped inside a function this time. When b is 2, the
division completes normally and the try block's return statement runs
immediately, returning 5.0 — the except block is never even reached.

When b is 0, Python raises a ZeroDivisionError partway through
evaluating a / b, exactly the exception type demonstrated in the
chapter's first try/except example. Execution jumps straight to
except ZeroDivisionError:, which returns None instead of letting the
exception propagate and crash the program.

Returning None specifically (rather than, say, printing an error
message from inside the function) keeps safe_divide usable as a
normal expression — callers can check "did this return None?" to
detect the failure case, rather than the function forcing its own
error-reporting behavior on every caller.