Challenge 3: Numbered List Output — Possible Solution
====================================================================

foods = ["Pizza", "Sushi", "Tacos"]

for i, food in enumerate(foods, start=1):
    print(f"{i}. {food}")

Output:
1. Pizza
2. Sushi
3. Tacos

WHY THIS WORKS AS AN ANSWER
------------------------------
enumerate(foods) alone would pair each food with a 0-based index (0,
1, 2), matching the chapter's own enumerate() example. Passing
start=1 as a second argument shifts that starting index to 1 instead
of 0, without changing anything else about how enumerate() works —
it's still handling the counting automatically, just from a different
starting point.

The f-string f"{i}. {food}" then formats each pair as "1. Pizza",
"2. Sushi", "3. Tacos" — a human-friendly numbered list, rather than
the default 0-based "0. Pizza" a plain enumerate(foods) would produce.