Exercise 2 - solution

Grades:
89.99 -> Excellent
90 -> Outstanding
84.99 -> Very Good
85 -> Excellent

Extra lines:
six_oz = 6 * OZ_TO_ML
print(f"6 oz cup = {six_oz:.0f} ml; a 5 ml slurp is {5 / six_oz:.1%}")

Output:
6 oz cup = 177 ml; a 5 ml slurp is 2.8%

84.99 lands in Very Good (80 to 84.99).